(81x^2-90x+25)=0

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Solution for (81x^2-90x+25)=0 equation: 



(81x^2-90x+25)=0

We get rid of parentheses

81x^2-90x+25=0

a = 81; b = -90; c = +25;
Δ = b2-4ac
Δ = -902-4·81·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{90}{162}=5/9$

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